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	<title>Istiyanto.Com - Media Online Belajar Matematika dan TIK &#187; snmptn</title>
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		<title>Soal UMPTN 1999</title>
		<link>http://istiyanto.com/soal-umptn-1999/</link>
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		<pubDate>Sat, 12 Dec 2009 10:57:59 +0000</pubDate>
		<dc:creator>istiyanto</dc:creator>
				<category><![CDATA[Matematika]]></category>
		<category><![CDATA[Prediksi]]></category>
		<category><![CDATA[prediksi um ugm]]></category>
		<category><![CDATA[snmptn]]></category>
		<category><![CDATA[Soal Matematika]]></category>
		<category><![CDATA[soal snmptn]]></category>
		<category><![CDATA[UM UGM]]></category>
		<category><![CDATA[umptn]]></category>

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		<description><![CDATA[Soal berikut merupakan soal matematika dasar UMPTN 1999 (waktu itu saya masih kelas II SMA). Soal ini merupakan soal gabungan antara deret aritmatika dan deret geometri. Simak ya, sampai akhir posting. Soal: Tiga bilangan membentuk barisan aritmatika. Jika suku ketiga ditambah 2 dan suku kedua dikurangi 2 diperoleh barisan geometri. Jika suku ketiga barisan aritmatika]]></description>
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